Let's see if anyone gets this (no, not just solving the integral), I was proud of my nerd-ability to figure it out right away (well, with help of my trusty TI-89).Like what you just read? Subscribe!
I do not get it, anyone want to fill me in?
The integral equals 1337And if you can solve it, it's proof you're 1337.
Dr. L337 is getting laid.
As far as I see the integral equals to 510734 = (7/2) * SQR(382). Even geeks make mistakes.
So you're saying that the integral of 7x is (7)*(x/2)? I think you need to revisit your calc 2 book.
Oh, and (7/2)*SQR(382)=68.4, not 510734... Like every math teacher never stops saying, check your work, son.
in this case SQR(x) stays for x*x (sorry for my Pascal notation :-).calc the value of antiderivative when the attribute is 382 and you'll get the answer. antiderivative can be found here: http://integrals.wolfram.com/index.jsp?expr=7*x&random=false:-)
yes, and to get the value of 1337, the correct expression is integral(7*dx, 0, 191).
http://m.wolframalpha.com/input/?i=integral%287*x%2C0%2Csqrt%5B382%5D%29&x=0&y=0I think you're missing that you evaluate the expression from 0 to the sqrt, not 0 to 382.
ah, my bad. did not notice the square root on the image. it appeared lines of "square root" are too thin for me.p.s. it seems Wolfram can be used as powerful online calculator.
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