Let's see if anyone gets this (no, not just solving the integral), I was proud of my nerd-ability to figure it out right away (well, with help of my trusty TI-89).
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Tuesday, April 15, 2008
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12 comments:
leet!
I do not get it, anyone want to fill me in?
The integral equals 1337
And if you can solve it, it's proof you're 1337.
Dr. L337 is getting laid.
As far as I see the integral equals to 510734 = (7/2) * SQR(382). Even geeks make mistakes.
So you're saying that the integral of 7x is (7)*(x/2)? I think you need to revisit your calc 2 book.
Oh, and (7/2)*SQR(382)=68.4, not 510734... Like every math teacher never stops saying, check your work, son.
in this case SQR(x) stays for x*x (sorry for my Pascal notation :-).
calc the value of antiderivative when the attribute is 382 and you'll get the answer. antiderivative can be found here: http://integrals.wolfram.com/index.jsp?expr=7*x&random=false
:-)
yes, and to get the value of 1337, the correct expression is integral(7*dx, 0, 191).
http://m.wolframalpha.com/input/?i=integral%287*x%2C0%2Csqrt%5B382%5D%29&x=0&y=0
I think you're missing that you evaluate the expression from 0 to the sqrt[382], not 0 to 382.
ah, my bad. did not notice the square root on the image. it appeared lines of "square root" are too thin for me.
p.s. it seems Wolfram can be used as powerful online calculator.
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